Reaction of Sodium Metabisulfite with Chlorine Compounds
Sodium metabisulfite (Na2S2O5) is a strong reducing agent and is commonly used to remove chlorine compounds from solutions, especially in water treatment and laboratory processes.
Chemical Reaction with Chlorine (Cl2)
When sodium metabisulfite reacts with chlorine, it effectively reduces chlorine to chloride ions while being oxidized itself. The main reaction is as follows:
Na2S2O5 + 2 Cl2 + 3 H2O → 2 NaHSO4 + 4 HCl
- Chlorine (Cl2) is reduced to chloride ions (Cl-).
- Sodium metabisulfite is oxidized to sodium bisulfate (NaHSO4).
Reaction with Hypochlorite Compounds
Sodium metabisulfite can also react with hypochlorite ions (OCl-), which are found in common bleach solutions. The reaction dechlorinates the solution:
Na2S2O5 + 4 NaOCl + 2 H2O → 4 NaCl + 2 NaHSO4
- Hypochlorite is reduced to chloride ions.
- The process neutralizes active chlorine and produces sodium chloride and sodium bisulfate.
Summary
- Sodium metabisulfite is an effective dechlorinating agent.
- It reduces chlorine compounds (both Cl2 and OCl-) to harmless chloride ions.
- The main byproducts are sodium bisulfate (NaHSO4) and sodium chloride (NaCl).